To properly neutralize 10N NaOH, how much 2.5N Sulfuric Acid will you need?

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Multiple Choice

To properly neutralize 10N NaOH, how much 2.5N Sulfuric Acid will you need?

Explanation:
To determine how much 2.5N sulfuric acid is needed to neutralize 10N sodium hydroxide, we use the concept of equivalent weight and the neutralization reaction ratio. In a neutralization reaction, one equivalent of an acid neutralizes one equivalent of a base. Sodium hydroxide is a strong base, and sulfuric acid is a strong acid. The reaction between sulfuric acid (H₂SO₄) and sodium hydroxide (NaOH) is represented as follows: \[ H₂SO₄ + 2 NaOH \rightarrow Na₂SO₄ + 2 H₂O \] From this equation, we see that one mole of sulfuric acid neutralizes two moles of sodium hydroxide, which indicates that the reaction ratio of H₂SO₄ to NaOH is 1:2. Given that you have 10N NaOH, you need to find out how many equivalents of NaOH you have in a given volume. If you're working with 1 liter (1,000 mL) of 10N NaOH, it would contain 10 equivalents of NaOH. Since the neutralization ratio is 2:1, you would need: \[ \text{Equivalent of

To determine how much 2.5N sulfuric acid is needed to neutralize 10N sodium hydroxide, we use the concept of equivalent weight and the neutralization reaction ratio.

In a neutralization reaction, one equivalent of an acid neutralizes one equivalent of a base. Sodium hydroxide is a strong base, and sulfuric acid is a strong acid. The reaction between sulfuric acid (H₂SO₄) and sodium hydroxide (NaOH) is represented as follows:

[ H₂SO₄ + 2 NaOH \rightarrow Na₂SO₄ + 2 H₂O ]

From this equation, we see that one mole of sulfuric acid neutralizes two moles of sodium hydroxide, which indicates that the reaction ratio of H₂SO₄ to NaOH is 1:2.

Given that you have 10N NaOH, you need to find out how many equivalents of NaOH you have in a given volume. If you're working with 1 liter (1,000 mL) of 10N NaOH, it would contain 10 equivalents of NaOH. Since the neutralization ratio is 2:1, you would need:

[ \text{Equivalent of

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